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willbeatthegmat
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The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44. Find the first three terms of the AP?
WIKI has a perfect explanation, which you fill find very useful:willbeatthegmat wrote:The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44. Find the first three terms of the AP?
Beat me too it! Nice work cramya and logitech!cramya wrote:In an AP
an = a1+ (n-1) d
where a - first term n- number of terms and d-> common difference
Given a4+a8 = 24
a6+a10 = 44
a4 = a1+3d
a8 = a1+7d
a6 = a1+5d
a10 = a1+9d
a1+3d+a1+7d = 24 -> 2a1+10d = 24->a1+5d=12 (1)
a1+5d+a1+9d = 44-> 2a1+14d = 44->a1+7d=22 (2)
Solve for a1 and d from 1 and 2
d=5
a1=-13
a2=a1+d = -13+5 = -8
a3= a1+2d = -13+2(5) = -3
Hope this helps.
Whats the answer given?