1/2SH = 2*1/2sh
SH = 2sh
S = 2sh/H--equ 1
Now since the triangles are similar: s/S = h/H
Substitute this in equ 1
S = 2 s*(s/S)
S^2=2s^s
S = sqrt2.s
Option C.
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GMAT Prep Similar Triangles
Source: Beat The GMAT — Problem Solving |
Another property of similar triangles is
ratio of areas = square of ratio of sides
A-area of big trngle = 2a (given) S - SIDE
a - area of smaller trngl s - side
a / A = (s / S) ^ 2
a / 2a = s^2 / S^2
S = SQRT(2)s
C)
ratio of areas = square of ratio of sides
A-area of big trngle = 2a (given) S - SIDE
a - area of smaller trngl s - side
a / A = (s / S) ^ 2
a / 2a = s^2 / S^2
S = SQRT(2)s
C)
