Given that A = 3y + 8x, B = 3y - 8x, C = 4y + 6x, and D = 4y - 6x, what is the value of x*y?
1)AB + CD = -275
2)AD - BC = 420
1)AB + CD = -275
2)AD - BC = 420
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Can someone elaborate on this!?shankar.ashwin wrote:BIMO
(1) gives you 2 possibilities.
For statement 1, if you plug in the values of A,B,C, and D, multiply it out and simplify everything, you get 4x^2-y^2=9. Factoring, we get (2x+y)(2x-y)=9. This will be true if 2x-y=9 and 2x+y=1. Solving this system gives us x=5/2 and y=4 and x*y=10. Or it could be that 2x-y=3 and 2x+y=3. Solving this system gives us x=3/2 and y=0 or x*y=0. There are infinitely many other possibilities for x*y, as there is no reason to restrict our attention to integer factors of 9, but this is enough to prove statement 1 insufficient.gmatblood wrote:Can someone elaborate on this!?shankar.ashwin wrote:BIMO
(1) gives you 2 possibilities.
Thanks.
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