Strings

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Strings

by nahid078 » Wed Jul 01, 2015 11:56 am
How many different strings of letters can be made by reordering of the word SUCCESS?
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by Brent@GMATPrepNow » Wed Jul 01, 2015 12:08 pm
nahid078 wrote:How many different strings of letters can be made by reordering of the word SUCCESS?
When we want to arrange a group of items in which some of the items are identical, we can use something called the MISSISSIPPI rule. It goes like this:

If there are n objects where A of them are alike, another B of them are alike, another C of them are alike, and so on, then the total number of possible arrangements = n!/[(A!)(B!)(C!)....]

So, for example, we can calculate the number of arrangements of the letters in MISSISSIPPI as follows:
There are 11 letters in total
There are 4 identical I's
There are 4 identical S's
There are 2 identical P's
So, the total number of possible arrangements = 11!/[(4!)(4!)(2!)]

------------------

In SUCCESS:
There are 7 letters in total
There are 2 identical C's
There are 3 identical S's
So, the total number of possible arrangements = 7!/[(2!)(3!)]
= 420

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by nahid078 » Wed Jul 01, 2015 1:29 pm
Thank you.

If you don't mind I have a request for you since i have found your solutions very clear and easy.

https://www.beatthegmat.com/sum-of-creat ... 84173.html
https://www.beatthegmat.com/selecting-door-t284174.html
https://www.beatthegmat.com/sound-can-tr ... 84148.html

Somebody answered for the 1st two questions and I know his answers are wrong. I just need you to make my concept clear.

Thank you in advance. :)

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by nikhilgmat31 » Fri Jul 03, 2015 12:26 am
7! / ( 3!2!)
= 420