BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Circle Question

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 141
Joined: Fri Mar 06, 2009 8:40 am

Circle Question

by hmboy17 » Thu Apr 09, 2009 9:25 am
Please see the attachement.
If Angle AOB is 90 degree. and two points A (S,T) & B (-Root3,1) are on circle. Then find out the point S. Point O (0,0)
Can some one tell me way to solve this question?
Attachments
Questions.JPG
Top
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 92
Joined: Wed Mar 25, 2009 12:13 pm
Thanked: 10 times

by moutar » Thu Apr 09, 2009 10:12 am
Length of radius of the circle:
{(-root(3))^2 + 1^2}^1/2
= {3+1}^1/2
= 2

Angle made between lines BO and the y axis:
cos x = 1/2 (adj/hyp)
x = 60 deg

Therefore angle made between y axis and AO:
90 - 60 = 30

Length of AO = 2

So x co-ordinate of A = 2 sin 30 = 1

OA?

There must be a quicker way of doing that. but this checks it.
Top
Post new topic Post Reply
• Page 1 of 1