-
srinivasapriyan.r
- Junior | Next Rank: 30 Posts
- Posts: 18
- Joined: Sat May 04, 2013 9:49 am
Now, coming back to the original question:
Q: x = ?In the figure shown, what is the value of x ?
(1) The length of line segment QR is equal to the length of line segment RS.
(2) The length of line segment ST is equal to the length of line segment TU.
St1:
QR = RS
This is not at all helpful and in no way helps to find x (cant use similar triangles property, etc)
INSUFFICIENT
St2:
ST = TU
This is not at all helpful and in no way helps to find x (cant use similar triangles property, etc)
INSUFFICIENT
St1+St2:

In the bigger right angled ∆RPT the sum of the angles R + T = 180 - 90 = 90
But In the isosceles ∆RQS, R + a + a = 180 ; R + 2a = 180 ; R = 180 - 2a
Similarly, In the isosceles ∆STU, T + b+ b = 180 ; T + 2b = 180 ; T = 180 - 2b
Thus, 180 - 2a + 180 - 2b = 90
We can find a + b.

Now a + x + b = 180 and thus we can find x
SUFFICIENT
Answer C
























