ganeshrkamath wrote:abhasjha wrote:There are 8436 steel balls, each with a radius of 1 cm stacked in a pile with 1 ball on top,3 balls in the second layer,6 in the 3rd layer,10 in the fourth and so on, the number of horizontal layers in the pile is
(a) 30
(b) 42
(c) 36
(d)45
1 + 3 + 6 + 10 + ..... + Tn = 8436
Tn = n(n+1)/2
sum(Tn) =
sum(n^2 + n)/2
8436 =
(n(n+1)(2n+1)/6 + n(n+1)/2)/2
16872 = n(n+1)(2n+1)/6 + n(n+1)/2
33744 = n(n+1)(2n+1)/3 + n(n+1)
33744 = n(n+1)*((2n+1)/3 + 1)
33744 = n(n+1)*(2n+4)/3
33744 = n(n+1)(n+2)*2/3
50616 = n(n+1)(n+2)
So the units digit is 6.
Only option that satisfies this is [spoiler](C)[/spoiler]
Cheers
ganeshrkamath's solution above is awesome, and it uses some great number sense to arrive at the correct answer without tedious calculations. So, all of this seems to make it GMAT-worthy, but
in my opinion, the question is not GMAT-worthy.
Here's why.
To solve this question, we need an important formula that ganeshrkamath applies above
in green
Essentially, the formula says
1² + 2² + 3² + ... + n² = n(n+1)(2n+1)/6
ganeshrkamath summarized it as: sum(n^2) = n(n+1)(2n+1)/6
We do not to know this formula for the GMAT. In other words, it's not a tested concept. For that reason, the question is out of scope.
Of course, if there's a way to solve the question using concepts found in the GMAT syllabus, then the question might be GMAT-worthy, but from what I can tell, it's out of scope.
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
