In the xy plane, point P has coordinates (a,b) and point Q has coordinates (c,d). What is the distance between P and Q?
1) b - d = 4
2) a - c = 3
1) b - d = 4
2) a - c = 3
distance between two points in a xy plane is given by sqrt((y2-y1)^2+(x2-x1)^2)
1) gives you y2-y1, but nothing on x2-x1, so insufficient.
2) gives you x2-x1, but nothing on y2-y1, so insufficient.
using bot you get the distance as sqrt(4^2+3^2) = sqrt(16+9) = sqrt(25) = 5.
Answer is C
