BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATBootcamp Starts Sep 21
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE BOOTCAMP

Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

Sep 21 to Oct 9, 2026

Schedule
Mon to Fri · 7:00 to 10:00 PM ET
Included
Live classes + 6 months of TTP OnDemand
  • Boost your GMAT score in less than one month in a live online class
  • 6 months access to TTP OnDemand video courses included
View bootcamp & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Strange question. help pls.

Expert replies
by tanviet » Fri Oct 30, 2009 5:29 am
this is from 15 testset.

on an aerial photograph, the surface of a pond appears as circular region of radius 7/16 inch. if a distance of 1 inch on the photogragh corresponds to an actual distance of 2 miles, which of the following is the closest estimate of the actual surface area of the pond, in square miles.

a,1.3
b,2.4
c,3.0
d,3.8
e,5.0
Join the discussion
Source: — Problem Solving |

by BuckeyeT » Fri Oct 30, 2009 6:38 am
r= 7/16 in
1 in = 2 miles

r = (7/16) in * (2 miles / 1 in)
r = 7/8 miles

A = pi * r^2
A = ~3 * (7/8)^2
A = ~3 * 49/64
A = ~ 147/64
A = 2.something

Only one answer is in this area: B.
Join the discussion

by NikolayZ » Fri Oct 30, 2009 6:43 am
In this problem, you need to convert photo scale into the actual sclae. i.e. the radius of photo to the radius of actual place in the air.
s0, 7/16*2=14/16.
knowing the formula of the area of the cirlce - (pi)r^2
the area will be - 196/256(pi) ( pi=3.14 so it would be approximately 3)
after simplification - 49/64*(pi), round both numerator and denominator to the closest number.
50/65*3=10/13*3=30/13, approximately 2.3 smth.
so the answer should be b.
Join the discussion