How many combinations of three letters taken from letters (a,a,b,b,c,c,d) are possible?
A. 12
B. 13
C. 35
D. 36
E. 56
A. 12
B. 13
C. 35
D. 36
E. 56
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Case 1: All 3 letters are differentgmatter2012 wrote:How many combinations of three letters taken from letters (a,a,b,b,c,c,d) are possible?
A. 12
B. 13
C. 35
D. 36
E. 56
Thank you MitchGMATGuruNY wrote:Case 1: All 3 letters are differentgmatter2012 wrote:How many combinations of three letters taken from letters (a,a,b,b,c,c,d) are possible?
A. 12
B. 13
C. 35
D. 36
E. 56
Number of combinations of 3 that can be formed from 4 letters {a, b, c, d} = 4C3 = 4.
Case 2: 2 letters are the same
Number of options for the letter that appears twice = 3. (a, b, or c.)
Number of options for the third letter = 3. (Any of the other 3 letters.)
To combine these options, we multiply:
3*3 = 9.
Total options = 4+9 = 13.
The correct answer is B.
Some test-takers might find it easier simply to write out all of the possible combinations:
Case 1: All 3 letters are different
abc
abd
acd
bcd
4 options.
Case 2: 2 letters are the same
aab
aac
aad
bba
bbc
bbd
cca
ccb
ccd
9 options.
Total options = 4+9 = 13.
I'm pretty sure that, in its current form, this would never be a true GMAT question. It's too ambiguous.eski wrote:Is this a right GMAT question and of what difficulty?
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