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Source: — Data Sufficiency |

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by Anurag@Gurome » Mon May 02, 2011 8:52 pm
alltimeacheiver wrote:ques if xy not # t0, what is the value of (x-y/y)-(x-y/x)

1 x=y

2 x=2
Please confirm if the question is as follows:

If xy is not equal to 0, what is the value of [(x - y)/y] - [(x - y)/x]?
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by alltimeacheiver » Tue May 03, 2011 8:01 pm
yes this is question to find value
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by Anurag@Gurome » Tue May 03, 2011 8:12 pm
alltimeacheiver wrote:yes this is question to find value
If xy is not equal to 0, what is the value of [(x - y)/y] - [(x - y)/x]?

Solving [(x - y)/y] - [(x - y)/x], we get (x² - 2xy + y²)/xy = (x - y)²/xy
So, now the question is If xy is not equal to 0, what is the value of (x - y)²/xy?

(1) x = y implies x - y = 0.
So, (x - y)²/xy = 0
Hence, (1) is SUFFICIENT.

(2) x = 2 does not give the value of y.
So, (2) is NOT SUFFICIENT.

The correct answer is A.
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by MAAJ » Wed May 04, 2011 2:14 pm
[(x - y)/y] - [(x - y)/x] = ?
[(x/y) - 1] - [1 - (y/x)] = ?

1) x = y
[(x/x) - 1] - [1 - (x/x)] = ?
[1 - 1] - [1 - 1] = ?
0 - 0 = 0

2) x = 2
[(2/y) - 1] - [1 - (y/2)] = ?
Not sufficient to answer
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