sofiasol wrote:Is x/5 an integer?
1) x/12.35 is an integer.
2) x/6,360 is an integer.
The solution says 2) alone is sufficient, but 1) alone is not sufficient.
I got the opposite... Could someone explain why? Please.
The following we can draw if x/5 is an integer.
1. x = 0
2. x = a positive mutiple of 5: 5, 10, 15, 20, ...
3. x = a negative mutiple of 5: -5, -10, -15, -20, ...
If we are able to establish that x ALWAYS falls in at least one of the three, the answer is YES; however, we are able to establish that x DOES NOT fall in any of the three, the answer is NO. In both the case, the question is answerable.
The question is inconclusive or unanswerable if x sometimes falls in at least one of the three, but also sometimes does not fall in them.
Let us take each statement one by one.
S1: x/12.35 is an integer.
Whenever you see a fraction asking to be tested whether it is an integer, always first test two values: 0 and the given number (here 12.35).
We see that if x = 0 or 12.35, x/12.35 is an integer.
At x=0, the fraction x/5 is an integer; however, at x=12.35, the fraction x/5 is not an integer. No unique answer. Insufficient.
S2: x/6,360 is an integer.
We see that if x = 0 or 6,360, x/6,360 is an integer.
At x=0, the fraction x/5 is an integer; moreover, at x=6360, the fraction x/5 is also an integer.
Should we try more? Well, there is no need, but let's try to understand better.
Since x/6,360 is an integer, x must be a multiple of 6360. Or, x belongs to set: {0, +/-6360, +/-6360*2, +/-6360*3,+/-6360*4,+/-6360*4...}
We if plug-in any of the values given in the set in x/5, x is always divisible by 5, making x/5 an integer. A unique answer. Sufficient.
Correct answer:
B
Hope this works.
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