manhatan gmat 3

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manhatan gmat 3

by resilient » Sun Feb 17, 2008 11:19 pm
If n is a non-negative integer such that 12n is a divisor of 3,176,793, what is the value of n12 – 12n ?


a.- 11
b.- 1
c.0
d.1
e.11

qa is b i chose D
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Re: manhatan gmat 3

by stellategang » Mon Feb 18, 2008 12:40 pm
Enginpasa1 wrote:If n is a non-negative integer such that 12n is a divisor of 3,176,793, what is the value of n12 – 12n ?


a.- 11
b.- 1
c.0
d.1
e.11

qa is b i chose D
something is wrong with your question

n*12 - 12*n = 0

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corrected

by resilient » Mon Feb 18, 2008 2:40 pm
If n is a non-negative integer such that 12n is a divisor of 3,176,793, what is the value of n^12 – 12^n ?


a.- 11
b.- 1
c.0
d.1
e.11

qa is b i chose D
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by cris » Mon Feb 18, 2008 3:20 pm
Engin this is a really tricky question.

What you have to find oout first is that n=0

So: 0^12=0 ; 12^0=1

So: 0-1= -1 ......B is the correct answer

You get it?

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12n

by dragonheart » Mon Feb 18, 2008 6:08 pm
well dear

i am not getting the qns. since 12n is divisor of x and x isnot a multiple of zero how come we get the value of n = 0.

also is it 12n, 12^n, 12*n.
with no offence, plz do not post such ambigous qns.

thanx

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how do you get n

by resilient » Mon Feb 18, 2008 7:10 pm
the question hangs on the understanding of the multipilicity of that number. since the 3176793 ends in 3 the 12n must be compatible but i dont understand hwo n = 0?


tricky questions
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by Stuart@KaplanGMAT » Mon Feb 18, 2008 9:05 pm
Sorry, this question makes no sense at all.

If n is an integer (positive, negative or 0), there's no value of n that will make 12n a divisor (i.e. factor) of an odd number.

0 is a multiple of every number, it's a divisor of no numbers.
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by xilef » Fri Feb 22, 2008 3:37 pm
Wouldn't the only possible value for 12n be 1, in which case n=1/12 :

(1/12)^12-12^(1/12)=-1

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by Stuart@KaplanGMAT » Fri Feb 22, 2008 4:18 pm
xilef wrote:Wouldn't the only possible value for 12n be 1, in which case n=1/12 :

(1/12)^12-12^(1/12)=-1
Except that the question says:

"If n is a non-negative integer"

which is why there's no possible value for n that satisfies the requirement:

12n is a divisor of 3,176,793.
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question was posted incorrectly

by Edthesock » Wed Jan 21, 2009 3:11 pm
I want to point out that the question is NOT 12n and n12 - 12n, it is the following:

If n is a non-negative integer such that 12^n is a divisor of 3,176,793, what is the value of n^12 - 12^n.

12^0 = 1, and one is a divisor of all numbers (possibly with some exception I'm not thinking of, like 0 or infinity or something).

n^12 - 12^n = 0 - 1 = -1 so B is our answer

I wish people would post correctly, stuff like this just frustrates everyone.