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Tough Geometry Question

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by Mo2men » Thu Jul 27, 2017 6:59 am
In triangle ABC, if angle ABC is 30 degrees, AC = 2 * √2 and AB = BC = X, what is the value of X?

A) √3 - 1

B) √3 + 2

C) (√3 - 1) / 2

D) (√3 + 1) / 2

E) 2 * (√3 + 1)

OA: E
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by [email protected] » Thu Jul 27, 2017 12:13 pm
Hi Mo2men,

The answer choices to this question are designed in such a way that you can use a bit of logical estimation and eliminate all of the wrong answers.

Based on the description in the prompt, we're dealing with an ISOSCELES triangle (30/75/75) and the 'short side' is 2√2. While you might not immediately know the value of √2, you probably know that 14^2 = 196, so (1.4)^2 = 1.96... thus, you can reasonably estimate √2 = 1.4

Thus, 2√2 is approximately 2.8). By definition, the two longer sides would be considerably BIGGER than 2.8 (not necessarily double, but the ratio of the angles- 75 to 30 - means that X would NOT be close to 2.8), so we can now estimate if any of the answers would be too small relative to what X should probably be.

√3 is clearly less than √4 - so √3 is clearly LESS than 2. Using the same math that you used to determine the approximate value of √2, you can determine that √3 is about 1.7

Answer A: (1.7) - 1 = (0.7). NOT a match.
Answer B: (1.7) + 2 = (3.7). Maybe... but this answer is relatively close to 2.8.....
Answer C: (0.7)/2 = (0.35). NOT a match.
Answer D: (2.7)/2 = (1.35). NOT a match.
Answer E: 2(2.7) = (5.4)

Given the ratio of angles, Answer E makes a lot more 'sense' from a mathematical standpoint than Answer B does.

Final Answer: E

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by GMATGuruNY » Thu Jul 27, 2017 4:23 pm
The following figure is known as the Ailles rectangle:
Image
The figure above illustrates the following:
In a 15-75-90 triangle, (shorter leg)/(hypotenuse) = (√3 - 1)/(2√2).
Mo2men wrote:In triangle ABC, if angle ABC is 30 degrees, AC = 2 * √2 and AB = BC = X, what is the value of X?

A) √3 - 1

B) √3 + 2

C) (√3 - 1) / 2

D) (√3 + 1) / 2

E) 2 * (√3 + 1)
If we split the given triangle in half, the following figure is yielded:
Image

In the 15-75-90 triangle on the right, the shorter leg = √2 and the hypotenuse = X.
Since (shorter leg)/(hypotenuse) = (√3 - 1)/(2√2), we get:
(√2)/X = (√3 - 1)/(2√2)

X(√3 - 1) = (√2)(2√2)

X(√3 - 1) = 4

X = 4/(√3 - 1)

X = [4(√3 + 1)] / [(√3 - 1)(√3 + 1)]

X = [4(√3 + 1)] / (3 - 1)

X = [4(√3 + 1)] / 2

X = 2(√3 + 1).

The correct answer is E.
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by Matt@VeritasPrep » Mon Aug 07, 2017 12:02 am
Not that I'm against the Ailles rectangle, but I don't think we should assume students would know that or dream it up.

How about this, a very GMAT appropriate way that only requires drawing a few lines and knowing the ratios of 45-45-90 and 30-60-90s. No algebra is used here, and the steps are color coded to the diagram, so you can see what is added at each step:

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by Matt@VeritasPrep » Mon Aug 07, 2017 12:05 am
Two important takeaways from my approach:

1) Drawing a well-chosen line can make seemingly impossible geometry questions very accessible, so when in doubt, ask yourself if you can draw something;

2) Always remind yourself that a GMAT problem can't rely on anything beyond the basics you were taught. You aren't expected to know what to do with a 75° angle - this isn't trigonometry - but if you realize that 75° = 30° + 45°, all of a sudden you can use some very friendly and familiar triangles that you WERE taught.
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