A and S

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AIM TO CRACK GMAT: Senior | Next Rank: 100 Posts; Posts: 80; Joined: Sat Sep 15, 2012 1:07 am; Thanked: 1 times; Followed by:1 members

A and S

by AIM TO CRACK GMAT » Wed Nov 06, 2013 11:58 pm

A and S are running a race of 5000 metres. A finishes the race 40 secs before S. If S's speed while running is 25m/sec. what is A's speed

20m/sec
28.75m/sec
31.25m/sec
34.50m/sec

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Source: Beat The GMAT — Problem Solving | Wed Nov 06, 2013 11:58 pm

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[email protected]: Elite Legendary Member; Posts: 10392; Joined: Sun Jun 23, 2013 6:38 pm; Location: Palo Alto, CA; Thanked: 2867 times; Followed by:511 members; GMAT Score:800

by [email protected] » Thu Nov 07, 2013 12:32 am

Hi Aim,

While this question is NOT written in GMAT "style" it is based on the Distance Formula, which you'll use a couple of times on Test Day.

D = R(T)

S's Formula: 5000 = (25m/sec)(T)
T = 5000/25 = 200 seconds

Since A finishes 40 seconds BEFORE T, then....
A's Formula: 5000 = R(160 seconds)
R = 5000/160 = 125/4 = 31.25m/sec

Final Answer:C

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Rich

Last edited by [email protected] on Thu Nov 07, 2013 1:06 am, edited 1 time in total.

Contact Rich at [email protected]

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ganeshrkamath: Master | Next Rank: 500 Posts; Posts: 283; Joined: Sun Jun 23, 2013 11:56 pm; Location: Bangalore, India; Thanked: 97 times; Followed by:26 members; GMAT Score:750

by ganeshrkamath » Thu Nov 07, 2013 12:55 am

AIM TO CRACK GMAT wrote:A and S are running a race of 5000 metres. A finishes the race 40 secs before S. If S's speed while running is 25m/sec. what is A's speed

20m/sec
28.75m/sec
31.25m/sec
34.50m/sec

Time taken by S to cover 5000 meters at 25m/sec = (distance/speed) = 5000/25 = 200 seconds

Time taken by A to cover 5000 meters = 200 - 40 = 160 seconds

Speed of A = (distance/time) = 5000/160 = 250/8 = 31.25 m

Choose C

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