BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Integers

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pmFollowed by: 511 members
Location: Palo Alto, CA
Thanked: 2867 times
GMAT Score:800

by [email protected] » Sun Nov 24, 2013 8:00 pm
Hi parulmahajan89,

In these types of "stats" questions, it's important to pay attention to all of the limitations that the information provides:

We're told that there are 15 different integers with a median of 25 and a range of 25. We're asked for the maximum possible value of any integer in the set.

Since there are 15 different integers and the median is 25, then 7 numbers are BELOW 25 and 7 numbers are ABOVE 25.

- - - - - - - 25 - - - - - - -

Since the range is 25, to make the largest number as large as possible, we need to make the smallest number as large as possible also. Here's how THAT would happen:

18 19 20 21 22 23 24 25 - - - - - - -

If the biggest "smallest" number is 18, and the range is 25, then the biggest number is 18 + 25 = 43

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 490
Joined: Thu Jul 04, 2013 7:30 amFollowed by: 5 members
Location: Chennai, India
Thanked: 83 times

by Uva@90 » Sun Nov 24, 2013 8:05 pm
parulmahajan89 wrote:A set of 15 different integers has a medium of 25 and range of 25. What is the greatest possible integer that could be in this set?

a) 32
b) 37
c) 40
d) 43
e) 50

Why is answer not 50?
Hi Parulmahajan89,
In this question you have to note many words,
1) 15 different integers
2) greatest possible integer

Coming to Answer,
Median is 25 and Range is 25 and there are 15 different integers,

_ _ _ _ _ _ _ 25 _ _ _ _ _ _ _


To the left of 25 there should be 7 and to the right of 25 there should be 7 numbers.

But what question say is greatest possible integer. So we need to minimize to the left so that we can get the max number on the right side,
18,19,20,21,22,23,24,25_ _ _ _ _ _ _
And the range given is 25.
Hence max number should be 18+25 = 43.

Hence Answer is D

Regards,
Uva.
Known is a drop Unknown is an Ocean
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1556
Joined: Tue Aug 14, 2012 11:18 pmFollowed by: 34 members
Thanked: 448 times
GMAT Score:650

by theCodeToGMAT » Sun Nov 24, 2013 9:52 pm
Range = Largest - Smallest

15 Terms & 25 is median.. So that means we have 7 terms on left of Median.

TO maximize the RHS of Median we must minimize the LHS of Median... we can do this by subtracting "1" as we got left from Median.

So, Smallest = 25-7 = 18

==> 25 = Largest - 18

Largest = 43
[spoiler]
{D}[/spoiler]
R A H U L
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 74
Joined: Fri May 11, 2012 9:06 pm

by parulmahajan89 » Mon Nov 25, 2013 9:04 pm
Thank you everyone
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 74
Joined: Fri May 11, 2012 9:06 pm

by parulmahajan89 » Mon Nov 25, 2013 9:06 pm
Thank you everyone
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 74
Joined: Fri May 11, 2012 9:06 pm

by parulmahajan89 » Mon Nov 25, 2013 9:07 pm
Thank you everyone
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 447
Joined: Fri Nov 08, 2013 7:25 amFollowed by: 1 member
Thanked: 25 times

by Mathsbuddy » Tue Nov 26, 2013 12:09 am
x = maximum
m = minimum
Range = x - m = 25

Median is at position (15 +1)/2 = 8
Therefore there are 15 - 8 = 7 numbers both above and below it
To maximise x, we need to maximise m
Maximimum value of m = 25 - 7 = 18
x = 25 + 18 = 43 (D)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1