Laps on a track

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Laps on a track

by chieftang » Tue Jan 03, 2012 4:20 pm
Starting at the same time and from the same point on a circular track, Bill and Chris run laps in the same direction. Bill runs one lap every 1 1/3 minutes. Chris runs one lap every 2 1/2 minutes. After how many minutes will they both arrive simultaneously at the starting point?

(A) 6 minutes
(B) 10 minutes
(C) 16 minutes
(D) 20 minutes
(E) 22 minutes

Source: MOEMS problem bank.
Source: — Problem Solving |

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by pemdas » Tue Jan 03, 2012 4:59 pm
Bill's speed 3/4 lap per minute
Chris' speed 2/5 lap per minute

t*(3/4) = t*(2/5) + C, where C is difference in distance (whole laps) between Bill and Chris

hence, take diff. 3/4-2/5=C/t or 7/20=C/t, C is difference in laps (seven laps) and 20 is time in min-s required for condition in the question

d
chieftang wrote:Starting at the same time and from the same point on a circular track, Bill and Chris run laps in the same direction. Bill runs one lap every 1 1/3 minutes. Chris runs one lap every 2 1/2 minutes. After how many minutes will they both arrive simultaneously at the starting point?

(A) 6 minutes
(B) 10 minutes
(C) 16 minutes
(D) 20 minutes
(E) 22 minutes

Source: MOEMS problem bank.
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by user123321 » Tue Jan 03, 2012 5:03 pm
This is a standard problem and we can get by taking lcm between 4/3 & 5/2 which is 20.

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by GMATGuruNY » Tue Jan 03, 2012 5:09 pm
chieftang wrote:Starting at the same time and from the same point on a circular track, Bill and Chris run laps in the same direction. Bill runs one lap every 1 1/3 minutes. Chris runs one lap every 2 1/2 minutes. After how many minutes will they both arrive simultaneously at the starting point?

(A) 6 minutes
(B) 10 minutes
(C) 16 minutes
(D) 20 minutes
(E) 22 minutes

Source: MOEMS problem bank.
ALWAYS LOOK AT THE ANSWER CHOICES.

Bill's rate = 4/3 minutes per lap.
Chris's rate = 5/2 minutes per lap.

In order for Bill and Chris both to arrive back at the starting point, the number of laps run by each runner must be an integer.
Thus, when the correct answer choice is divided by each rate, the result in each case must be an integer.
To divide by the fractions above, we multiply by their reciprocals: 3/4 and 2/5.
Thus, the correct answer choice must be a multiple of 4 and 5.

The correct answer is D.
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by pemdas » Tue Jan 03, 2012 5:12 pm
yes, provided reciprocal of time is found as work/time (work=1) for speed 3/4 & 2/5. Their difference is the distance or position assigned. 7/20 cannot be further reduced as a ratio, hence not possible to have less than 7 laps difference in distance, but it's possible to have 14 or 21 laps difference accordingly with 40 and 60 minutes. Thus, this question falls under not quite standard category of GMAT questions as we are required to return to the initial position or count the whole difference units. Other sol-s possible, tried to come up with this one
user123321 wrote:This is a standard problem and we can get by taking lcm between 4/3 & 5/2 which is 20.

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by chieftang » Tue Jan 03, 2012 5:49 pm
Ya, I actually converted to seconds and then factored to determine LCM(80,150) = 1200. Then 1200/60 = 20. Maybe that was the most cumbersome method of those shown in the thread! But it worked. Answer D.