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Is m odd?

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by gauravgundal » Sun May 17, 2009 2:48 am
IMO -b

Stmt 1
m + n = odd
either m or n can be odd
not suff

Stmt 2

n+m=n^2+5

m=n^2+5-n

if n is odd n^2 is odd
and
odd-odd= even
but n^2 is odd
odd+even = odd

if n is even ,n^2 is even
odd -even=5-n=odd you can even take '-' values of n

and
n^2=even
even-odd or even +odd = odd


so
B is suff
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by aj5105 » Sun May 17, 2009 7:58 am
n,m are integers.

Statement (1) : n + m = odd

m can be odd or m can be even.


Statement (2) : n + m = n^2 + 5

n^2 - n = 5 - m

n(n - 1) = 5 - m

n(n -1) has to be even.So, m has to be even.

(B)
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by iamcste » Sun May 17, 2009 8:21 am
aj5105 wrote:n,m are integers.

Statement (1) :
Statement (2) : n + m = n^2 + 5

n^2 - n = 5 - m

n(n - 1) = 5 - m

n(n -1) has to be even.So, m has to be even.
(B)
do you mean to say, m has to be Odd

for a difference to be eve, both should be either even or odd...since 5 is odd, M must be odd
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by aj5105 » Sun May 17, 2009 8:50 am
Yeah, I mean odd.
iamcste wrote:
aj5105 wrote:n,m are integers.

Statement (1) :
Statement (2) : n + m = n^2 + 5

n^2 - n = 5 - m

n(n - 1) = 5 - m

n(n -1) has to be even.So, m has to be even.
(B)
do you mean to say, m has to be Odd

for a difference to be eve, both should be either even or odd...since 5 is odd, M must be odd
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