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Price Reductions

by harsh.champ » Fri Feb 19, 2010 8:06 am
The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of

A. 45%
B. 40%
C. 35%
D. 32.5%
E. 30%

Read the question carefully
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by thephoenix » Fri Feb 19, 2010 8:09 am
harsh.champ wrote:The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of

A. 45%
B. 40%
C. 35%
D. 32.5%
E. 30%

Read the question carefully
IMO B
its 4/5(3/4x)=3/5 of x
red is x-3x/5=2x/5=40% of x
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by harshavardhanc » Fri Feb 19, 2010 10:57 am
harsh.champ wrote:The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of

A. 45%
B. 40%
C. 35%
D. 32.5%
E. 30%

Read the question carefully

........ -25%............-20%
100 ----------->75--------> 60
.........-25...............-15

overall reduction 40% :)
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Harsha
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by shashank.ism » Sat Feb 20, 2010 5:41 am
harsh.champ wrote:The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of

A. 45%
B. 40%
C. 35%
D. 32.5%
E. 30%

Read the question carefully
Let x be the initial price
after 1st reduction price = x-0.25x = 0.75 x
after second reduction price = 0.75x - 0.75x (0.2) = 0.8 x 0.75 x = 0.6x
so total reduction = x=0.6x = 0.4x
=[spoiler] 40% Ans B[/spoiler]
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by gmatmachoman » Sat Feb 20, 2010 5:45 am
I prefer plugging in Numbers when it comes to percents

Let X =100

after 25% reuction : 75 :

after 20 % reduction : 60

So at the end : 100-60: 40

40% reduction!!
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by shashank.ism » Sat Feb 20, 2010 7:18 am
gmatmachoman wrote:I prefer plugging in Numbers when it comes to percents

Let X =100

after 25% reuction : 75 :

after 20 % reduction : 60

So at the end : 100-60: 40

40% reduction!!
yeah gmatmochan that is also indeed a good approach to consider the things as 100 and then solve the problem sometimes it solves in seconds... here too acc to ur method its solvable in mind.only...thanks
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by harshavardhanc » Mon Feb 22, 2010 6:46 am
shashank.ism wrote:
gmatmachoman wrote:I prefer plugging in Numbers when it comes to percents

Let X =100

after 25% reuction : 75 :

after 20 % reduction : 60

So at the end : 100-60: 40

40% reduction!!
yeah gmatmochan that is also indeed a good approach to consider the things as 100 and then solve the problem sometimes it solves in seconds... here too acc to ur method its solvable in mind.only...thanks
what's done above is the meaning of percent : per cent ( for every 100) ! :)

and that's the whole concept ! :)
Regards,
Harsha
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