bobdylan wrote:Train Y leaves NY at 1:00 am and travels east at an average speed of x mph. If train Z leaves NY at 2:00 am and travels east, at what average rate of speed will train Z have to travel in order to catch train Y at exactly 5:30 am?
a. 5/6 x
b. 9/8 x
c. 6/5 x
d. 9/7 x
3/2 x
Time and rate are RECIPROCALS.
Y takes 4.5 hours to travel the same distance that Z travels in 3.5 hours.
Since the ratio of the TIMES = (4.5)/(3.5) = 9/7, the ratio of the RATES = 7/9.
Thus, if Y's rate = x = 7 miles per hour, then Z's rate = 9 miles per hour. This is our target.
Now we plug x=7 into the answers to see which yields our target of 9.
Only answer choice
D works:
(9/7)x = (9/7)7 = 9.
The correct answer is
D.
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