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by HSPA » Fri Mar 11, 2011 9:35 am
How did you get 22C19 .... I am getting 23C19
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by HSPA » Fri Mar 11, 2011 9:41 am
instead of 21 and 19 consider 3 M and 2 F and __ is the spaces

__ M __ M__ M __

So here you see we can fill 2F in 4 spaces ... so it is in 4C2 ways = (3+1)C2 = (21+1)C19 = 1540
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