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DS - Is n an integer (old question from the official guide)

Expert replies
by beyondenim1 » Wed Feb 02, 2011 6:19 am
Is n an integer ?

(1) n^2 is an integer

(2) √n is an integer


I understood statement 1 of why this is insufficient because the value of n could also be a non-integer and still yield an integer of its total value.

ex. n could be (√2) ^2 = equal to an integer 2.


What I do not understand is that in statement 2, we can also plug in a non-integer value for n such as √√81 (so we can assume that the value of n is √81, so overall becomes 4th root of 81), thus resulting to an integer 3.

So why is the answer b? It should be E because in both statements I plugged in √2 and √81. Both of which are NON-INTEGERS and thus, we cannot guarantee that n is an integer in either situation.
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Source: — Data Sufficiency |

by Night reader » Wed Feb 02, 2011 6:30 am
beyondenim1 wrote:Is n an integer ?

(1) n^2 is an integer

(2) √n is an integer


I understood statement 1 of why this is insufficient because the value of n could also be a non-integer and still yield an integer of its total value.

ex. n could be (√2) ^2 = equal to an integer 2.


What I do not understand is that in statement 2, we can also plug in a non-integer value for n such as √√81 (so we can assume that the value of n is √81, so overall becomes 4th root of 81), thus resulting to an integer 3.

So why is the answer b? It should be E because in both statements I plugged in √2 and √81. Both of which are NON-INTEGERS and thus, we cannot guarantee that n is an integer in either situation.
st(2) √n is an integer implies only such n which under squared root is integer. Sufficient, as √n integer --> (√n)^2 is also the integer
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by GMATGuruNY » Wed Feb 02, 2011 7:23 am
beyondenim1 wrote:Is n an integer ?

(1) n^2 is an integer

(2) √n is an integer


I understood statement 1 of why this is insufficient because the value of n could also be a non-integer and still yield an integer of its total value.

ex. n could be (√2) ^2 = equal to an integer 2.


What I do not understand is that in statement 2, we can also plug in a non-integer value for n such as √√81 (so we can assume that the value of n is √81, so overall becomes 4th root of 81), thus resulting to an integer 3.

So why is the answer b? It should be E because in both statements I plugged in √2 and √81. Both of which are NON-INTEGERS and thus, we cannot guarantee that n is an integer in either situation.
√81 = 9, which is an integer. There is no non-integer value that will satisfy statement 2, so statement 2 is sufficient.
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by beyondenim1 » Thu Feb 03, 2011 9:11 pm
@GMATGuruNY

What I mean is that n could also equal √81 , meaning under a square root so the overall result would be √√81 (4th root of 81) the result is 3 which is an integer.

I don't think n is necessarily an integer here, the value of n is √81 which is not an integer and √√81 yields a value of 3.

Please Explain. Thanks in advance
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by GMATGuruNY » Thu Feb 03, 2011 9:44 pm
beyondenim1 wrote:@GMATGuruNY

What I mean is that n could also equal √81 , meaning under a square root so the overall result would be √√81 (4th root of 81) the result is 3 which is an integer.

I don't think n is necessarily an integer here, the value of n is √81 which is not an integer and √√81 yields a value of 3.

Please Explain. Thanks in advance
When you say that √81 is a non-integer, you are incorrect. √81 IS an integer, because √81 = 9 -- just as √25 is an integer, because √25 = 5, and 6/2 is an integer, because 6/2 = 3. How the value is notated doesn't matter. If the result is an integer, the value is an integer.
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I unlock the best way for YOU to solve problems.

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by beyondenim1 » Thu Feb 03, 2011 9:53 pm
@GMATGuruNY

Oh yeah. I forgot! It is definitely an integer just as 10/5. Thank you so much for clearing that up.
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