If (2^x)(3^y) = 288 where x and y are positive integers, then (2^x-1)(3^y-2) =?
a - 16
b - 24
c - 48
d - 96
e - 144
OA A
a - 16
b - 24
c - 48
d - 96
e - 144
OA A
Moonlinte,
Prime factorize 288 = 2 ^ 5 * 3 ^ 2
x=5 y = 2
Therefore 2 ^ (5-1) * 3 ^ (2-2)
= 2 ^ 4 * 3 ^ 0 (A^0 IS 1- any non zero integer raised to 0 is 1)
= 2 ^4
=16
A)
