(1) If x = -2, y = -1, then x² = 4, y² = 1. Here |x| > |y|. This will hold true for positive values of x and y.rcsrini wrote:Following DS question is from GMATPrep.
Is |x| > |y| ?
1. x^2 > y^2
2. x > y
Can you please help with explaination ?
It can be observed that |x| > |y| if x² > y²; SUFFICIENT.
(2)If x = 5, y = 3, then x > y and |x| > |y|
If x = -3, y = -4, then x > y but |x| < |y|
No definite answer; NOT sufficient.
The correct answer is A.
