BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Please help Gmat prep 2 PS: a certain car averages..

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Wed May 28, 2008 11:07 am

Please help Gmat prep 2 PS: a certain car averages..

by yichunette » Wed May 28, 2008 12:58 pm
A certain car averages 25 miles per gallon of gasolin when driven in the city and 40 miles per gallon when driven on the highway. According to these rate, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

Answer: 36

Please explain how to solve this problem.

Thank you!
:) :)
Yi
Top
Source: — Problem Solving |
Newbie | Next Rank: 10 Posts
Posts: 2
Joined: Wed May 28, 2008 2:34 pm

by malammik » Wed May 28, 2008 8:47 pm
How many gallons of gas will the car consume driving in the city? How about driving on the highway? Now you know total gallons and total miles, you can calculate average miles per gallon.
Top
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Wed May 28, 2008 1:29 pm

Total Mile/Gallon Solution--I think

by rachaelholland » Thu May 29, 2008 11:16 am
The problem asks for the average miles per gallon. You need to divide the total number of miles driven by the total miles per gallon. Total Miles/Total Gallons= Total Miles Per Gallon. You know from the problem that the total miles driven was 10 plus 50=60 miles total.

Now, to get the total miles per gallon, you need to divide the total miles by the total gallons.

First, for the city trip, you know the car was driven 10 miles, getting 25 miles per gallon. Therefore, you need to solve for how many gallons were consumed.

Set it up like this: 10 miles/xgallons =25miles/one gallon. Then, solve for x. To do this, I set up a proportion and cross multiplied. X = .4 gallons.

Then, do the same thing for the highway trip. 50 miles/x gallons=40 miles/1gallon. Again, solve for x. X=1.25

Now you have the amount of gallons driven for each scenario. Plug in to the Total equation==> 60/ (.4 +1.25)==> 60/(1.65)=36.36

I hope the rounding is acceptable. Let me know what you think!
Top
Master | Next Rank: 500 Posts
Posts: 112
Joined: Wed Jan 20, 2010 5:46 am
Thanked: 1 times

by Thouraya » Fri Apr 22, 2011 8:05 am
Why do we divide by average number of miles per gallon (25+50=75) not by the actual numbers?
Top
User avatar
Legendary Member
Posts: 582
Joined: Tue Mar 08, 2011 12:48 am
Thanked: 61 times
Followed by:6 members
GMAT Score:740

by force5 » Fri Apr 22, 2011 9:06 am
Although i really dont know the authenticity of the question as it requires an assumption. the answer will come close to 36. Is it a Gmat question?
Top
Senior | Next Rank: 100 Posts
Posts: 43
Joined: Sat Jan 15, 2011 11:26 am
Thanked: 9 times

by tgou008 » Tue Jun 28, 2011 6:28 pm
I also encountered this problem on my GMAC practice test today. In fact, it was my last question and I was soo pressed for time that I had to guess without even reading it - not suprisingly I got it wrong.

However, in my post exam review I decided to tackle the question before scouting out an answer and came up with the following approach.


City = 25m/gallon x 10m = 250
Highway = 40m/gallon x 50m = 2000
City + Highway / Total Actual Miles = (250 + 2000) / (10 + 50) = 2250 / 60 = 35 5/6

Therefore, the answer is closest to 36.
Effectively, I used a weighted average - although it's a little different to the technique shown above. Is this ok?
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 143
Joined: Sat Nov 06, 2010 9:06 pm
Thanked: 10 times
Followed by:1 members

by edvhou812 » Tue Jun 28, 2011 8:37 pm
Total Miles Driven: 10+50 = 60
Highway mpg: Drove 50 miles at rate of 40mpg, so consumed 1 10/40 = 1 1/4 = 5/4 gallons
City mpg: Drove 10 miles at rate of 25 mpg, so consumed 10/25 = 2/5 gallons

5/4+2/5= 25/20+8/20 = 33/20

60/33/20 = 1200/33 = About 36
Top
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Tue Mar 22, 2011 6:11 pm

by jshas » Tue Jun 28, 2011 9:11 pm
tgou008 wrote:I also encountered this problem on my GMAC practice test today. In fact, it was my last question and I was soo pressed for time that I had to guess without even reading it - not suprisingly I got it wrong.

However, in my post exam review I decided to tackle the question before scouting out an answer and came up with the following approach.


City = 25m/gallon x 10m = 250
Highway = 40m/gallon x 50m = 2000
City + Highway / Total Actual Miles = (250 + 2000) / (10 + 50) = 2250 / 60 = 35 5/6

Therefore, the answer is closest to 36.
Effectively, I used a weighted average - although it's a little different to the technique shown above. Is this ok?
2250/60 is 37.5, not 35 5/6
Last edited by jshas on Tue Jun 28, 2011 9:15 pm, edited 1 time in total.
Top
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Tue Jun 28, 2011 9:12 pm
yichunette wrote:A certain car averages 25 miles per gallon of gasolin when driven in the city and 40 miles per gallon when driven on the highway. According to these rate, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

Answer: 36

Please explain how to solve this problem.

Thank you!
:) :)
Yi
Per means division. Miles per gallon means miles/gallons.

City miles:Highway miles = 10:50 = 1:5.
Any values that conform to this ratio will yield the same average miles per gallon.

To make the math easy, plug in numbers that are multiples of 25 and 40.
Let city miles = 200 and highway miles = 1000. (200:1000 = 1:5.)
Gas used in the city = 200/25 = 8.
Gas used on the highway = 1000/40 = 25.
Total gas used = 8+25 = 33.
Total Miles/Total Gas = 1200/33 = 400/11 ≈ 36.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Tue Mar 22, 2011 6:11 pm

by jshas » Tue Jun 28, 2011 9:14 pm
Can anyone explain why you have to convert to gallons instead of using weighted average. I used the weighted average method and it provides an answer of 37.5...

(1/6) (25) + (5/6) (40) = 37.5
Top
Master | Next Rank: 500 Posts
Posts: 112
Joined: Wed Jan 20, 2010 5:46 am
Thanked: 1 times

by Thouraya » Fri Sep 16, 2011 5:07 am
Hi,

Sorry I didn't understand this question. Can someone please elaborate on the answer? Thanks!
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 496
Joined: Tue Jun 07, 2011 5:34 am
Thanked: 38 times
Followed by:1 members

by sl750 » Sat Sep 17, 2011 7:06 am
Average speed = Total distance/Total time

Total distance here = 10+50 = 60
Total time = 10/25+50/40

Avg Speed=60/330/200 = 60*200/330 = 36.3mph
Top
Post new topic Post Reply
• Page 1 of 1