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sameerballani
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Is |x-y| > |x|- |y| ?
a)y<x
or x-y>0 and thus l.h.s = x-y
if x>0,y>0 r.h.s. = x-y thus l.h.s.=r.h.s. and l.h.s is not greater than r.h.s.
if x>0,y<0 r.h.s. = x-(-y) = x+y. as y<0, (x-y)>(x+y) or l.h.s > r.h.s.
Insufficient.
b)xy<0 => x and y are of different signs
if x>0,y<0 r.h.s. = x-(-y) = x+y. also l.h.s. = x-y.
as y<0, (x-y)>(x+y) or l.h.s > r.h.s.
if x<0,y>0 r.h.s. = (-x)-y (r.h.s. can be seen as difference of 2 positive numbers as -x is +ve and y is +Ve)
l.h.s = y-x. (l.h.s can be seen as sum of 2 +ve numbers as x itself is -ve)
thus l.h.s.>r.h.s.
IMO B
