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Got stuck in a bit confusing question (Geometry)

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by naveendevaraj » Fri Oct 08, 2010 7:31 am
Image

The figure above shows two lines intersecting at the point O. If the lines are rotated about
O at the same rate and in the directions shown until AB is perpendicular to CD , through how many degrees
must each line move ?

A) 90 -Θ
b) 90 -Θ/2
C) 90 +Θ/2
d) (90+Θ)/2
e) (90+2Θ)/2

Explanations are welcomed.Thank you
Answer : D
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Source: — Problem Solving |

by shovan85 » Fri Oct 08, 2010 7:39 am
Let theta be @ here.
First think how much angle will it be required for each line to be coincident.
it will be @/2.

After both lines become coincident if you rotate each in the mentioned direction by 90/2 = 45 to get AB perpendicular to CD.

Thus the answer will be 45+@/2

or (90+@)/2.

IMOD
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by naveendevaraj » Fri Oct 08, 2010 7:51 am
thanks..
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by this_time_i_will » Fri Oct 08, 2010 7:53 am
suppose angle b/w the lines is 0. i.e. both lines lie on one another.
now wee need to move both lines in opposite direction, so that they are perpendicular.
a careful observation will tell that both line sud move 45 degree.

so, in the given options, put theta = 0 and see which option gives you 45. it is D.
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by GMATGuruNY » Fri Oct 08, 2010 8:04 am
naveendevaraj wrote:Image

The figure above shows two lines intersecting at the point O. If the lines are rotated about
O at the same rate and in the directions shown until AB is perpendicular to CD , through how many degrees
must each line move ?

A) 90 -Θ
b) 90 -Θ/2
C) 90 +Θ/2
d) (90+Θ)/2
e) (90+2Θ)/2

Explanations are welcomed.Thank you
Answer : D
Plug in Θ = 10.
Since the lines are rotating toward each other, in order to become perpendicular, they must cover the 10 degrees between them and then rotate 90 degrees more: 10+90 = 100 degrees.
So each line must rotate 100/2 = 50 degrees. This is our target answer.

Now we plug Θ=10 into all the answers to see which gives us our target of 50.

Only answer choice D works:
(90+Θ)/2 = (90+10)/2 = 50.

The correct answer is D.
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