BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

AP - Plz explain the sum

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pm
Location: Milpitas, CA
Thanked: 1854 times
Followed by:523 members
GMAT Score:770

by Anurag@Gurome » Fri Sep 02, 2011 2:59 am
anjana_gmat wrote:Q. In the sequence 1, 2, 2, 4, 4, 4, 4, 8, 8, 8, 8, 8, 8, 8, 8,......................., find the 1035th term of the sequence.
Note that,
  • 1st term of the sequence = 1 = 2^0
    2nd term of the sequence = 2 = 2^1
    3rd term of the sequence = 2 = 2^1
    4th term of the sequence = 4 = 2^2
    5th term of the sequence = 4 = 2^2
    6th term of the sequence = 4 = 2^2
    etc...
Hence, n-th term of the sequence = greatest integral power of 2 less than n

Therefore, 1035th term of the sequence = greatest integral power of 2 less than 1035 = 1024 = 2^10
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 359
Joined: Wed Mar 11, 2009 4:37 am
Location: Kolkata, India
Thanked: 50 times
Followed by:2 members

by Abhishek009 » Fri Sep 02, 2011 6:39 am
anjana_gmat wrote:Q. In the sequence 1, 2, 2, 4, 4, 4, 4, 8, 8, 8, 8, 8, 8, 8, 8,......................., find the 1035th term of the sequence.
1 will have 1 terms

2 will have 2 terms

4 will have 4 terms

8 will have 8 terms

16 will have 16 terms

32 will have 32 terms

64 will have 64 terms

128 will have 128 terms

256 will have 256 terms

512 will have 512 terms

Add them up U get 1023

So definitely U need to proceed further


Go further 1024 will have 1024 terms


Hence U can confidently claim the 1035th term of the sequence will be 1024.....
Abhishek
Top
Post new topic Post Reply
• Page 1 of 1