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Six countries

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Source: — Data Sufficiency |

by amising6 » Wed Jun 16, 2010 6:34 pm
universal condition
6 countries
total representatives
75

1) one of the country sent 41

so remaining countries can send 34 remaining candidate in many may
let the five candidate have a-2,a-1,a,a+1,a+2
sum of this should be equal to 34
5a=34 a=6.8
taking approx values
5,4,7,8,10

ohter values can be 5,3,7,8,11
or 5,2,7,8,12
or 5,1,7,8,13


2)A should be less than 12

so if we take only this condition remaining 5 can also take many values so many solution

now combining 1 and 2
one country=41
a=11
again can take many values as seen in the above two condiitoin
one comndition where a would be less than 10
will be 41,6,4,7,8,9 a=9 second largest but not atleast 10 less than 10
so answer choice is E
Ideation without execution is delusion
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by ssuarezo » Thu Jun 17, 2010 12:48 pm
amising6 wrote:universal condition
6 countries
total representatives
75

1) one of the country sent 41

so remaining countries can send 34 remaining candidate in many may
let the five candidate have a-2,a-1,a,a+1,a+2
Amising:
Why do you assume that the numbers are consecutives? why a-2,a-1,a,a+1,a+2? this could be 20, 2, 3, 7, ...
Silvia
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by aks16189 » Sun Jun 20, 2010 10:58 pm
let us try and see the max and min number that A can send,

for 1) it is obvious that A cannot send 41 because then he wil be the highest, but we know he is 2nd highest.
So A is one of the countries which send a total of 34 reps

the max A can be 24 with B C D & E having sent 1 2 3 & 4

min A can be 9 with B C D & E sending 8 7 6 & 4 {beacause he has to be highest among the 5}

so, 9<=A<=24, which doesnt prove whether A is at least 10 or not...

similarly for 2)

A ha fewer than 12 reps so it can be anything =>5 {considering the other 4 countries having sent minimum i.e. 1 2 3 & 4}

so, 5<=A<=11, which doesnt prove whether A is at least 10 or not...

now evn if we combine both,

9<=A<=11
which again doesnt prove whether A is at least 10 or not...

so the correct option is E
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by akhpad » Mon Jun 21, 2010 1:52 am
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by Patrick_GMATFix » Sat Jul 17, 2010 8:51 am
This is also discussed at https://www.beatthegmat.com/p-c-t61738.html

This type of question can often be solved by doing your best to prove that you can get two different answers from each statement. If you can get 2 answers using values that agree with he statement as well as the prompt (the question stem), you will have proven that the statements are not sufficient.

The same technique can be used to evaluate the statements together. In this case, be sure to use values that agree with the prompt as well as with both statements. To save time, see whether the values you've used to check previous statements can be used again.

The answer is E. A detailed solution and step-by-step video solution are available at GMATPrep Question 1097.

Good luck,
-Patrick
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by outreach » Sat Jul 17, 2010 12:08 pm
option 1

one country sent =41

remaining delgates=34
A can send 10 and other countries can send 9,8,5,3
A can send 9 and other countries can send 8,7,4,6

not suff


option 2

A can send 9,10,11 etc and other countris delegates can accordingly adjusted

not suff


1 and 2
not suff
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