you need to understand that "evenly distributed" here means evenly spaced, which means that a,b,c d are in AP.
b-a = c-b
2b= 2^18+2^17
hence b= 3.2^16
common difference will be 2^18-3.2^16
= 2^16
hence d = 2^18+ 2^16 = 5.2^16
tough one!!!!!!!!!
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force5
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No problem runzun here it goes.
b-a= c-b
2b=c+a
putting values (c=4^9 = 2^18)
2b= 2^18+2^17
= 2^17(2+1) [taking 2^17 common]
2b= 3.2^17
b= 3.2^17/2
= 3.2^17.2^-1
= 3.2^16 [powers added]
common diff = c-b
2^18-3.2^16
2^16(2^2-3) [ taking 2^16 common]
2^16 (4-3)
2^16
now d will be c+ common difference
2^18+2^16
2^16(2^2+1)
2^16(4+1)
5.2^16
hope it helps....
b-a= c-b
2b=c+a
putting values (c=4^9 = 2^18)
2b= 2^18+2^17
= 2^17(2+1) [taking 2^17 common]
2b= 3.2^17
b= 3.2^17/2
= 3.2^17.2^-1
= 3.2^16 [powers added]
common diff = c-b
2^18-3.2^16
2^16(2^2-3) [ taking 2^16 common]
2^16 (4-3)
2^16
now d will be c+ common difference
2^18+2^16
2^16(2^2+1)
2^16(4+1)
5.2^16
hope it helps....
