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Night reader
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Volume of C1 = pi * r^ 2 * h
Volume of C2 = a^3
Is pi * r ^ 2 * h > a ^ 3 ?
(1)
r = a
Is pi * a ^ 2 * h > a ^ 3
Is pi * h > a
Not enough ifo to answer the question
(2)
Going by the same logic above, question reduces to asking:
Is 2 * pi * r ^ 2 > a ^ 2
Again, not enough to answer the question
Combining 1 and 2
Is pi * a ^ 2 * 2 a > a ^ 3
Is 2 * pi * a ^ 3 > a ^ 3
This is certainly true, hence sufficient, so both statements combined are sufficient
(C)

















