BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

a multiplication game

Expert replies
by sanju09 » Fri Apr 10, 2009 5:17 am
In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiplies the integer on the card by the next larger integer. If each possible product is between 15 and 200, then the least and greatest integers on the cards could be
A. 3 & 15
B. 3 & 20
C. 4 & 13
D. 4 & 14
E. 5 & 12



OA C
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion
Source: — Problem Solving |

by kapsii » Fri Apr 10, 2009 5:41 am
Distilling the question for objective, we find it stating that for every number X in the given set of numbers multiply it by x+1 and the results should be between 15 and 200. Find the minimum and maximum number in the set.

I would start by examining the perfect squares between the ranges, they would give an indication of the numbers contained in the deck.

The nearest perfect square to 15 is 16 (4^2).
Nearest perfect square to 200 is 14^2.

examining the number 3, 3*4 is < 15, so, the minimum number has to be 4.
and 14^2 (196) is closest to 200, so we max value of product obtainable has to be 13*14 or 14*15 (which ever does not break the limit imposed by the range), so, go for 13*14, thus maximum number contained in the deck is 13.
Cheers,
Dubes
Join the discussion

by pallasy » Sun Mar 18, 2012 10:14 am
kapsii wrote:Distilling the question for objective, we find it stating that for every number X in the given set of numbers multiply it by x+1 and the results should be between 15 and 200. Find the minimum and maximum number in the set.

I would start by examining the perfect squares between the ranges, they would give an indication of the numbers contained in the deck.

The nearest perfect square to 15 is 16 (4^2).
Nearest perfect square to 200 is 14^2.

examining the number 3, 3*4 is < 15, so, the minimum number has to be 4.
and 14^2 (196) is closest to 200, so we max value of product obtainable has to be 13*14 or 14*15 (which ever does not break the limit imposed by the range), so, go for 13*14, thus maximum number contained in the deck is 13.
Why did you automatically assume 14 must be multiplied by 15? I understand the instructions say to multiply by the next highest integer, but since it's a "deck of cards," wouldn't 14 be the highest integer (J=11, Q=12, K=13, A=14)? If so, wouldn't 14 just need to be multiplied by 14 since there is no larger integer? 14x14 = 196, which means the answer would be 4 & 14? Please explain why this is not the case.
Join the discussion

by killer1387 » Mon Mar 19, 2012 4:13 am
sanju09 wrote:In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiplies the integer on the card by the next larger integer. If each possible product is between 15 and 200, then the least and greatest integers on the cards could be
A. 3 & 15
B. 3 & 20
C. 4 & 13
D. 4 & 14
E. 5 & 12



OA C
by options itself,
3*4=12<15
hence A/B out
4*5=20>15 ok
for 14*15=210>200 hence D is out
question asks of least E is out

hence C
Join the discussion

by PhDmessi » Mon Mar 19, 2012 5:26 am
If 15 is the smallest product, start by picking numbers:
- If the card is a 3, then eventually 3*4 = 12 --> too small
- Try 4: 4*5 = 20

Thus, least integer is 4, eliminate answer choice A,B and E.

Anwer choice C and D have 13 and 14 left, try both:
- 13*14 = 182
- 14*15 = 210 --> too large

Thus, 13 is the greatest integer on the cards.

Correct answer is C.
Never give up!
Join the discussion