smclean23 wrote:If xy=1, what is the value of 2^(x+y)^2/2^(x-y)^2
OA is D.
PLEASE EXPLAIN.
2^(x+y)^2/2^(x-y)^2
Numerator = 2^(x+y)^2 = 2^(x^2 + y^2 + 2xy) = 2^x^2 * 2^y^2 * 2^2xy
Denominator = 2^(x-y)^2 = 2^(x^2 + y^2 - 2xy) = 2^x^2 * 2^y^2 / 2^2xy
2^x^2 * 2^y^2 * 2^2xy / 2^x^2 * 2^y^2 / 2^2xy
2^2xy * 2^2xy = 2^2 * 2^2 = 4 * 4 = 16












