BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Functions

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 18
Joined: Tue May 05, 2009 11:03 am

by vitaly » Fri May 08, 2009 7:51 pm
f(10, 15) = f(25, 14), of course it's the largest. Answer is A.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 682
Joined: Fri Jan 16, 2009 2:40 amFollowed by: 1 member
Thanked: 32 times

by Vemuri » Fri May 08, 2009 11:17 pm
vitaly wrote:f(10, 15) = f(25, 14), of course it's the largest. Answer is A.
The second condition is: f(x,y+1) = f((x,y),y). How did you derive f(25,10)?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 319
Joined: Wed Feb 04, 2009 10:32 amFollowed by: 9 members
Location: Delhi
Thanked: 84 times

by sureshbala » Fri May 08, 2009 11:58 pm
The answer has to be E and not A.

With some serious observation you can find that f(x, y) = x i.e. that output of the function is independent of y.

We have f(x, 0) = x and f(x, y+1) = f(f(x, y), y)

From the second definition we have,

f(x, 1) = f(f(x, 0), 0) = f(x, 0) = x.

Hence f(x, 1) = x.

F(x, 2) = f(f(x, 1), 1) = f(x, 1) = x

Hence f(x, 2) = x.

So from here you can conclude that f(x, y) = x.

Hence the output of the function with largest value of x will be the largest.

So, the option E.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 682
Joined: Fri Jan 16, 2009 2:40 amFollowed by: 1 member
Thanked: 32 times

by Vemuri » Sat May 09, 2009 1:45 am
sureshbala wrote:The answer has to be E and not A.

With some serious observation you can find that f(x, y) = x i.e. that output of the function is independent of y.

We have f(x, 0) = x and f(x, y+1) = f(f(x, y), y)

From the second definition we have,

f(x, 1) = f(f(x, 0), 0) = f(x, 0) = x.

Hence f(x, 1) = x.

F(x, 2) = f(f(x, 1), 1) = f(x, 1) = x

Hence f(x, 2) = x.

So from here you can conclude that f(x, y) = x.

Hence the output of the function with largest value of x will be the largest.

So, the option E.
Hail Bala Hail !!! That was very smart of you. :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1