Chinn_asama wrote:Hi there
can anyone explain how the below problem can be solved?
An equilateral triangle of side 6cm has its corners cut off to form a regular hexagon. Area (in cm^2) of this regular hexagon will be?
thanx
The hexagon is composed of 6 equilateral triangles, each with a side of 2.
The area of an equilateral triangle = (s²√3)/4.
Total area of the 6 equilateral triangles = 6 * (2²√3)/4 = 6√3.
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