Help with simple maths problem

If (x-y)^2 = (x-y)(x-y)=0, then we can immediately say that (x-y)=0. This equation consists of the multiplication of two terms that are the same, so we need only consider one of the terms (since they are both the same).

(x-y)^2=0;
apply sqrt on both sides of the '=' sign
sqrt [ (x-y)^2 ] = sqrt (0); ( sqrt of (x-y)^2 is (x-y) & sqrt of 0 is 0)
so, (x-y) = 0.

Hope this helps.

In simpler terms,

if (x-y)^2 = 0,

that means (x-y)(x-y)=0

Simple logic- if ZERO is the product of two numbers, one or both of those numbers HAS to be ZERO.
For eg. (1)(0)=0, (0)(534)=0 or (0)(0)=0

In this case, since you're squaring (x-y), and the answer is 0, that means x-y HAS TO BE 0.

Other than the number 0, no other number can mathematically square to 0.

Hope that was easier to understand than lines of equations.