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GMAT prep question

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by saeed » Sun Jul 06, 2008 3:27 am
4c2X3c2
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by andreasonlinegr » Sun Jul 06, 2008 3:55 am
thank you .
i lost you in your answer. what's "c" in ur answer?
can you explain a bit more? thnx
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by saeed » Sun Jul 06, 2008 7:53 am
here C is for combination.
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by andreasonlinegr » Sun Jul 06, 2008 3:54 pm
can somebody help with the explanation of this?
thnx in advance

ps
Sorry saeed i still dont understand. whats' 4 combination 2....
provide the full logic and maths..
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by sibbineni » Sun Jul 06, 2008 4:00 pm
men-->4

women-->3

4 person task is to be formed with 2 men and 2 women.


selecting 2 men from 4 men can be done in 4C3 ways---(1)

selecting 2 women from 3 women can be done in 3C2 ways---(2)

so the no of ways of forming 4 person task is

4C3 * 3C2==>6*3

nCr=n!/(n-r)!*r!
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by dalwow » Wed Jul 09, 2008 9:05 am
sibbineni means 4c2 (not 4c3 which is in his post) which is 4!/2!*2! which equals 6.
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