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In how many ways can letters in the word "computer"

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by kanwar86 » Thu Sep 06, 2012 3:33 am
6!3! ways
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Kanwar

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by gmatter2012 » Thu Sep 06, 2012 3:35 am
kanwar86 wrote:6!3! ways
please can you provide the logic behind this. Please show how you arrived at this.
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by kanwar86 » Thu Sep 06, 2012 3:54 am
Number of vowels are 3 and they are all different...each vowel being represented by |
Number of consonants are 5 in number (all different)..each consonant represented by 0 (though they are all different..bear wid me :) )
Now, we want all vowels to be together
that is., |||00000 (this kind of structure)
So, what we do is we tie up these three vowels together and make it a single object (in square bracket) just like any other consonant [|||]00000, 0[|||]0000, 00[|||]000, 000[|||]00 etc.
So, in effect we have (8(total alphabets)-3(vowels to be kept together)+1(vowels are combined together to form a single object))= 6 different consonants which can be arranged in 6! ways.
But, that object in square brackets is composed of 3 vowels which can be mutually arranged in 3! ways.
Hence, the total number of ways = 6!*3!
Hope that helped.
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Kanwar

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by gmatter2012 » Thu Sep 06, 2012 5:15 am
kanwar86 wrote:Number of vowels are 3 and they are all different...each vowel being represented by |
Number of consonants are 5 in number (all different)..each consonant represented by 0 (though they are all different..bear wid me :) )
Now, we want all vowels to be together
that is., |||00000 (this kind of structure)
So, what we do is we tie up these three vowels together and make it a single object (in square bracket) just like any other consonant [|||]00000, 0[|||]0000, 00[|||]000, 000[|||]00 etc.
So, in effect we have (8(total alphabets)-3(vowels to be kept together)+1(vowels are combined together to form a single object))= 6 different consonants which can be arranged in 6! ways.
But, that object in square brackets is composed of 3 vowels which can be mutually arranged in 3! ways.
Hence, the total number of ways = 6!*3!
Hope that helped.
hi lots of thanks

here is a similar question
In how many ways can the letters of the word "double" be rearranged such that the order in which the vowels appear does not change?

This question says that they must appear in the same order and not together.how will the solution change , please do explain the logic.
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by kanwar86 » Thu Sep 06, 2012 5:42 am
gmatter2012 wrote:
kanwar86 wrote:Number of vowels are 3 and they are all different...each vowel being represented by |
Number of consonants are 5 in number (all different)..each consonant represented by 0 (though they are all different..bear wid me :) )
Now, we want all vowels to be together
that is., |||00000 (this kind of structure)
So, what we do is we tie up these three vowels together and make it a single object (in square bracket) just like any other consonant [|||]00000, 0[|||]0000, 00[|||]000, 000[|||]00 etc.
So, in effect we have (8(total alphabets)-3(vowels to be kept together)+1(vowels are combined together to form a single object))= 6 different consonants which can be arranged in 6! ways.
But, that object in square brackets is composed of 3 vowels which can be mutually arranged in 3! ways.
Hence, the total number of ways = 6!*3!
Hope that helped.
hi lots of thanks

here is a similar question
In how many ways can the letters of the word "double" be rearranged such that the order in which the vowels appear does not change?

This question says that they must appear in the same order and not together.how will the solution change , please do explain the logic.
The difference lies in the order of appearance of vowels in the word "Double"
That is, o should come before u, and u should come before e.
Hence, if we permute these three in a group only one combination follows the desired order.
Now we have 6 alphabets which can be re arranged in 6! ways
Out of 6! ways, there are 3! ways in which those three vowels have been rearranged.
But we are looking for permutations where that "one" order (discussed above) is being followed.
So, we divide 6!/3! = 720/6 = 120 ways (Ans)
Regards

Kanwar

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by GMATGuruNY » Thu Sep 06, 2012 6:01 am
gmatter2012 wrote: In how many ways can the letters of the word "double" be rearranged such that the order in which the vowels appear does not change?

This question says that they must appear in the same order and not together.how will the solution change , please do explain the logic.
I posted a solution here:

https://www.beatthegmat.com/tough-permut ... 20042.html
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As a tutor, I don't simply teach you how I would approach problems.
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by gmatter2012 » Thu Sep 06, 2012 6:40 am
kanwar86 wrote:
gmatter2012 wrote:
kanwar86 wrote:Number of vowels are 3 and they are all different...each vowel being represented by |
Number of consonants are 5 in number (all different)..each consonant represented by 0 (though they are all different..bear wid me :) )
Now, we want all vowels to be together
that is., |||00000 (this kind of structure)
So, what we do is we tie up these three vowels together and make it a single object (in square bracket) just like any other consonant [|||]00000, 0[|||]0000, 00[|||]000, 000[|||]00 etc.
So, in effect we have (8(total alphabets)-3(vowels to be kept together)+1(vowels are combined together to form a single object))= 6 different consonants which can be arranged in 6! ways.
But, that object in square brackets is composed of 3 vowels which can be mutually arranged in 3! ways.
Hence, the total number of ways = 6!*3!
Hope that helped.
hi lots of thanks

here is a similar question
In how many ways can the letters of the word "double" be rearranged such that the order in which the vowels appear does not change?

This question says that they must appear in the same order and not together.how will the solution change , please do explain the logic.
The difference lies in the order of appearance of vowels in the word "Double"
That is, o should come before u, and u should come before e.
Hence, if we permute these three in a group only one combination follows the desired order.
Now we have 6 alphabets which can be re arranged in 6! ways
Out of 6! ways, there are 3! ways in which those three vowels have been rearranged.
But we are looking for permutations where that "one" order (discussed above) is being followed.
So, we divide 6!/3! = 720/6 = 120 ways (Ans)
hi many many thanks

I am trying to clear this concept of occurring together, not occurring together, same order , not same order etc ..
As you seem to be good in combinations , I am going to bombard you with some questions which I have meticulously hand picked from various sources ,looking forward to your assistance ..and your help is highly appreciated.

request you to please keep track of my new topics . Again thanks !
Last edited by gmatter2012 on Thu Sep 06, 2012 9:46 am, edited 1 time in total.
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by gmatter2012 » Thu Sep 06, 2012 6:44 am
GMATGuruNY wrote:
gmatter2012 wrote: In how many ways can the letters of the word "double" be rearranged such that the order in which the vowels appear does not change?

This question says that they must appear in the same order and not together.how will the solution change , please do explain the logic.
I posted a solution here:

https://www.beatthegmat.com/tough-permut ... 20042.html
Mitch thank you
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