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g.shankaran
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II quadrant means x<0 and y >0
a) slope = -1/6
or y=x*(-1/6) + c where c is the y-intercept
now as x decreases, y increases and thus there will be a point when x<0 and y>0 and thus sufficient.
b)y-intercept=-6
y=mx-6 where m is the slope
if m<0, it will intersect.
but if m>0, say m=1, it won't
insufficient.
IMO A
