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Source: — Data Sufficiency |
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Re: geometry question

by maihuna » Sat Aug 29, 2009 5:49 am
n_niaz wrote:can anybody help me with this please
Any one will will do, in fact both the option are same and able to give the diff.

Solve it in this way: one common angle is 90, try to express the other Q and R in terms of common angle P and the two triangles.
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by sreak1089 » Sat Aug 29, 2009 6:37 am
IMO D
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by pradeepsarathy » Sat Aug 29, 2009 7:04 am
IMO E..
OA please?
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by sreak1089 » Sat Aug 29, 2009 7:23 am
My initial instinct was (E). However, as I looked at it closely, I find answer to be D. This is how I solved:

Assume angle PRS = x, then angle PRQ = 180-x

stmt # 1: angle QPR = 30

In triangle QPR, angle QPR + angle PRQ + angle PQR = 180
=> 30 + 180-x + angle PQR = 180
=> angle PQR = x - 30

Thus angle PRS (=x) is 30 degrees more than angle PQR (x-30). Hence stmt # 1 is SUFFICIENT.

stmt # 2: angle PQR + angle PRQ = 150
=> angle QPR = 30 (which is nothing but stmt # 1).

Hence stmt # 2 is also SUFFICIENT. Thus ans is D. IMO.
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