since triangle abc is isosceles, a=b, c is base and h is height we infer sqroot[a^2-(c^2/4)]=h and abc square will be c*sqroot[a^2-(c^2/4)]=36
we need to find perimeter (abc) or p=2a+c
from square (abc), sqroot[4a^2-c^2]=72/c ==> sqroot[(2a+c)(2a-c)]=72/c ==> sqroot(2a+c)=72/[c*sqroot(2a-c)] ==> 2a+c=(72^2)/[c^2*(2a-c)]
Bek wrote:If the area of an isosceles triangle is 18, what is its perimeter?
I couldn't handle it. Also I don't have the answer and answer choices.













