Permitations and combinations

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Permitations and combinations

by joinn » Wed Jul 06, 2011 1:59 am
The principal of a high school needs to schedule observations of 6 teachers. She
plans to visit one teacher each day for a workweek (Monday through Friday), so she
will only have time to see 5 of the teachers. How many different observation schedules
can she create?

the answer is 6!. how come it is 6!. what is the answer then when the days are six and the days are four.
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by Frankenstein » Wed Jul 06, 2011 2:07 am
Hi,
1st day - She can select any of the 6 teachers - 6ways
2nd day - 1 of the remaining 5 - 5ways
3rd day - 1 of the remaining 4 - 4 ways
4th day - 1 of the remaining 3 - 3 ways
5th day - 1 of the remaining 2 - 2 ways

So, total number of ways is 6.5.4.3.2 = 6!(6P5)
If the number of days is 6, then 6.5.4.3.2.1 = 6!
If the number of days is 4, then 6.5.4.3 = 6P4
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