ugoyal wrote:Q. A manufacturer produced x percent more video cameras in 1994 than in 1993 and y percent more video cameras in 1995 than in 1994. If the manufacturer produced 1,000 video cameras in 1993, how many video cameras did the manufacturer produce in 1995 ?
(1) xy = 20
(2) x + y + xy/100 = 9.2
Since the number of cameras produced in 1993 is given, all we need to know is
the percent increase from 1993 to 1995.
The percent increase -- up x% in 1994 and then up another y% in 1995 -- is going to be the same
no matter how many cameras were produced in 1993. To make the math easier, let's plug in that in 1993 the number of cameras produced was 100.
If 100 cameras were produced in 1993, the increase in the number of cameras produced in 1994 would be (x/100)*100 = x.
So the total number produced in 1994 would be 100+x.
In 1995, the increase in the number of cameras produced would be (y/100)(100+x) = y + xy/100.
Thus, the total increase from 1993 to 1995 would be (increase in 1994) + (increase in 1995) = x + y + xy/100.
Since we started with 100 cameras, this expression also represents the percent increase from 1993 to 1995.
So to have sufficient information,
we need to know the value of x + y + xy/100.
Statement 1:
If x=1 and y=20, x + y + xy/100 = 1 + 20 + (1*20)/100 = 21.2.
If x=4 and y=5, x + y + xy/100 = 4 + 5 + (4*5)/100 = 9.2.
Since the expression can take on different values, insufficient.
Statement 2:
Tells us that x + y + xy/100 = 9.2.
Sufficient.
The correct answer is B.
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