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ferpape: Newbie | Next Rank: 10 Posts; Posts: 8; Joined: Fri Aug 28, 2009 10:28 am

by ferpape » Wed Sep 02, 2009 9:37 am

I need help with this one...

Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but Peter only drove 2/5 of the total distance, what was the ratio of Peter's average speed to Tom's average speed?
1)1:5
2)2:5
3)1:2
4)3:5
5)2:3

Thanks

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Source: Beat The GMAT — Problem Solving | Wed Sep 02, 2009 9:37 am

PussInBoots: Master | Next Rank: 500 Posts; Posts: 157; Joined: Tue Oct 07, 2008 5:47 am; Thanked: 3 times

by PussInBoots » Wed Sep 02, 2009 10:24 am

Distance: 100
Peter drove 40, Tom drove 60
Time is t, same for both

Average speeds are 40/t and 60/t
(40/t) / (60/t) = 2/3

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tom4lax: Master | Next Rank: 500 Posts; Posts: 175; Joined: Mon Feb 09, 2009 3:57 pm; Thanked: 4 times

by tom4lax » Wed Sep 02, 2009 10:33 am

P = (2/5)/t * t = 2/5
T = (3/5)/t * t = 3/5

(2/5) / (3/5) = 2/3 answer is E

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ferpape: Newbie | Next Rank: 10 Posts; Posts: 8; Joined: Fri Aug 28, 2009 10:28 am

by ferpape » Wed Sep 02, 2009 3:17 pm

Thank you both!!

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8188; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Wed Dec 13, 2017 5:05 pm

ferpape wrote:
Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but Peter only drove 2/5 of the total distance, what was the ratio of Peter's average speed to Tom's average speed?
1)1:5
2)2:5
3)1:2
4)3:5
5)2:3

We can let the time driven by Peter and Tom = t. If we let the total distance = d, then Peter's distance = (2/5)d = 2d/5 and Tom's distance = (3/5)d = 3d/5.

Thus, Peter's rate is (2d/5)/t = 2d/5t and Tom's rate is (3d/5)/t = 3d/5t.

The ratio of Peter's average speed to Tom's average speed is (2d/5t)/(3d/5t) = 10dt/15dt = 2/3.

Answer: E

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