IMO D
1)2^|x|= 2^x
so |x|=x
so x>=0
SUFF
2)3^|x|<=3^x
i think 3^|x| can never be < 3^x
because minimum value of 3^|x| is 1 when x=0
for any other value 3^|x|>=3^x
so here only the equality holds true
3^|x|=3^x
this is same as statement 1.
SUFF
DS with modulus
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Source: Beat The GMAT — Data Sufficiency |
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tohellandback
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