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gmatblood: Master | Next Rank: 500 Posts; Posts: 489; Joined: Tue Jul 05, 2011 11:10 am; Thanked: 28 times; Followed by:5 members

Survey, from Knewton

by gmatblood » Sun Nov 06, 2011 11:12 am

In a survey of 348 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured?

(A) 7/12
(B) 8/41
(C) 91/348
(D) 1/8
(E) 41/91

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Source: Beat The GMAT — Problem Solving | Sun Nov 06, 2011 11:12 am

vaibhavgupta: Master | Next Rank: 500 Posts; Posts: 416; Joined: Tue Aug 30, 2011 2:18 pm; Location: Delhi, India; Thanked: 13 times; Followed by:9 members

by vaibhavgupta » Sun Nov 06, 2011 11:28 am

gmatblood wrote:In a survey of 348 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured?

(A) 7/12
(B) 8/41
(C) 91/348
(D) 1/8
(E) 41/91

IMO A

12.5% of 104=13
hence people who are neither= 203
probability that the person will neither work part time nor be uninsured=203/348

If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8086; Joined: Sat Apr 25, 2015 10:56 am; Location: Los Angeles, CA; Thanked: 43 times; Followed by:29 members

by Scott@TargetTestPrep » Tue Nov 12, 2019 7:03 pm

gmatblood wrote:In a survey of 348 employees, 104 of them are uninsured, 54 work part time, and 12.5 percent of employees who are uninsured work part time. If a person is to be randomly selected from those surveyed, what is the probability that the person will neither work part time nor be uninsured?

(A) 7/12
(B) 8/41
(C) 91/348
(D) 1/8
(E) 41/91