sukhman wrote:If k is a positive integer and n = k(k + 7), is n divisible by 6?

(1) k is odd

(2) When k is divided by 3 the remainder is 2.

Translate the question.

Does n have among its prime factors at least one 2 and one 3?

Statement 1:

If k is odd, then k + 7 is even. So if k + 7 is a factor of n, then n is even, meaning that n has 2 among its prime factors.

However k could be 3 or another positive integer.

If k = 3, then n has 3 among its prime factors.

If, for instance, k = 19, then k(k + 7) = 19(26) and n does not have 3 among its prime factors.

So there is not enough information for determining whether n has 3 among its prime factors.

Insufficient.

Statement 2:

This means that k = 3x + 2. So k + 7 = 3x + 9. So 3 is a factor of k + 7 and of n.

If k is even, then n has 2 among its prime factors. If k is odd, then k + 7 is even and n has 2 among its prime factors.

So Statement 2 makes clear that n has 2 and 3 among its prime factors and is divisible by 6.

Sufficient.

The correct answer is B.

If k is a positive integer and n = k(k + 7), is n divisible by 6?

(1) k is odd.

(2) When k is divided by 3, the remainder is 2.

Statement 1: k is odd
If k=1, then n = 1(1 + 7) = 8, which is NOT divisible by 6.
If k=3, then n = 3(3 + 7) = 30, which IS divisible by 6.
INSUFFICIENT.

Statement 2: When k is divided by 3, the remainder is 2
In other words, k is 2 more than a multiple of 3.
In math terms:
k = 3a + 2, where a is a nonnegative integer.
Options for k:
k = 2, 5, 8, 11...
If k=2, then n = 2(2 + 7) = 18, which is divisible by 6.
If k=5, then n = 5(5 + 7) = 60, which is divisible by 6.
If k=8, then n = 8(8 + 7) = 120, which is divisible by 6.
In every case, n is divisible by 6.
SUFFICIENT.

The correct answer is B.