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by agps » Sat Sep 08, 2007 2:37 am
from 1) x and y are either both positive and x>y or x and y have different signal and x> 0. more than 1 possible answer, insufficient.

from2) both x and y have the same signal negative or positive we don't know, insufficient

combining both, from 1) x is always positive and from 2) x and y both have the same signal, so both are positive. answer C
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Source: — Data Sufficiency |
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by Jameschan168 » Sun Sep 09, 2007 3:19 pm
Can someone explain what happens after we combine both stmts? I'm still a little confused with agps's explanation. Thanks.
agps wrote:from 1) x and y are either both positive and x>y or x and y have different signal and x> 0. more than 1 possible answer, insufficient.

from2) both x and y have the same signal negative or positive we don't know, insufficient

combining both, from 1) x is always positive and from 2) x and y both have the same signal, so both are positive. answer C
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by ri2007 » Sun Sep 09, 2007 9:02 pm
Jameschan168

A suggestion when u find it diff to relate to variables plug in values.

Take the question in discussion -

Statement 1 gives X>Y

So X can be 6 and Y can be 3 or X can be -3 and Y can be -6

Statement 2 gives X/y >1

If you look at the statement alone again X can be 6 and Y can be 3 or X can be -3 and Y can be -6

But if you combine the statement you know X > y so for x/y to be > 1 they will have to be positive. IF they were negative X/y would be a fraction and so less than 1
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by kajcha » Mon Sep 10, 2007 9:41 am
Stmt 1 - both, x and y, can be positive or negative. NOT SUFF

Stmt 2 - both will be negative or positive. NOT SUFF

Together - from stmt 2 |x|>|y| and stmt 1 satisfies only when both are positive. So SUFF

Ans C
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by gmatguy16 » Mon Sep 10, 2007 11:20 am
ans is correct e:
you guys did not consider x=-1/2 and y=-1.
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by gmatguy16 » Mon Sep 10, 2007 11:21 am
rather x=-1 and y=-1/2
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by kajcha » Mon Sep 10, 2007 12:40 pm
gmatguy16 wrote:rather x=-1 and y=-1/2
2x-2y will NOT be equal to 1

2*-1 - 2*(-1/2) = -2+1 = -1

Ans will be C
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by Jameschan168 » Tue Sep 11, 2007 10:50 am
Thanks ri2007.
ri2007 wrote:Jameschan168

A suggestion when u find it diff to relate to variables plug in values.

Take the question in discussion -

Statement 1 gives X>Y

So X can be 6 and Y can be 3 or X can be -3 and Y can be -6

Statement 2 gives X/y >1

If you look at the statement alone again X can be 6 and Y can be 3 or X can be -3 and Y can be -6

But if you combine the statement you know X > y so for x/y to be > 1 they will have to be positive. IF they were negative X/y would be a fraction and so less than 1
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