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mehravikas
- Legendary Member
- Posts: 1161
- Joined: Mon May 12, 2008 2:52 am
- Location: Sydney
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1)
S and T have the same total value.
S average < average T
It means S id divided by more than T
So S has more members than T
2)
Let's take example/counter-example so as to be sure it's insufficient.
S= 1 2 3 and T= 1 1 1 1 1 1
Median of S is greater, they have the same total value.
Members S < Members T
S= 1 3 3 and T= 2 2 3
Median of S is greater, they have the same total value.
Members S=Members T












