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by agps » Fri Aug 31, 2007 1:12 am
w=p/t-root(v) (not sure how to express this in english)
if w=2 when v=1 then p=2, because any root of 1 is always 1 (1 squared or cubed or 1^n always = 1) so w=p/1 if w=2 then p=2.

so for w=1/2 and v=64 we have 1/2=2/t-root(64) so t-root(64) = 4,
then t=3 (4^2=16, 4^3=4^2*4=64)
Answer C.
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Junior | Next Rank: 30 Posts
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Thanks.

by KL08 » Sat Sep 01, 2007 1:24 am
I thought it's t*v^(1/2), instead to the power. Thanks for your help.
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